Download Calculus With Analytic Geometry by George Simmons PDF
By George Simmons
Written by means of acclaimed writer and mathematician George Simmons, this revision is designed for the calculus direction provided in and 4 yr schools and universities. It takes an intuitive method of calculus and makes a speciality of the appliance of the way to real-world difficulties. through the textual content, calculus is taken care of as an issue fixing technology of tremendous power.
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000 . . (c) �; (e) -\149; (i) 2 (a) If n is even, prove that n2 is also even. (b) If n is odd, prove that n2 is also odd. 75 ; (f) (h) 3 1 12; (j) 2,f-. l/7r; Every integer is either even or odd. The even integers are those that are divisible by 2 , so n is even if and only if it has the form n = 2k for some integer k. The odd inte gers are those that have the form n = 2k + 1 for some integer k. In Problems 3- 12, rewrite the given expression without using the absolute value symbol. 3 17 - 1 81 .
A) a :s a; If a :s b and b :s a , what conclusion can be drawn about a and b? (a) If a < b is true, is it also necessarily true that a :s b? (b) If a :s b is true, is it also necessarily true that a < b? State whether each pair of points lies on a horizontal or a vertical line: (a) ( - 2, -5), ( - 2, 3); (b) (-2 , - 5), ( 7, -5); (d) (2, - I I ) , (2, 5); (c) ( -3 , 4), (6, 4); (f) (-7, -7), ( - 7, 7); (e) (2, 2), ( - 1 3, 2); (h) (- 1, -2), (2, - 2). (g) (3, 5), (3, -2); Three vertices of a rectangle are ( - I , 2), (3, -5), ( - I , - 5).
0, show that its equation can be written as a 11 12 (a, a b � + l'. = I a b · This is called the intercept form of the equation of a line. Notice that it is easy to put y = 0 and see that the line crosses the x-axis at x = and to put x 0 and see that the line crosses the y-axis at y = 9 Put each equation in intercept form and sketch the cor responding line: (a) 5x + 3y + 15 = O; (b) 3x = 8y 24; (c) y = 6 - 6x; (d) 2x - 3y = 9. 10 The set of all points (x, y) that are equally distant from the points P 1 ( - 1 , - 3) and P2 (5, - 1 ) is the per pendicular bisector of the segment joining these points.