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By Levi S. Shively

Spanish translation of the vintage college-level glossy geometry textbook

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Extra resources for Introducción a la geometría moderna

Example text

Let A be a circle in C given by the equation αzz + βz + βz + γ = 0, where α, γ ∈ R and β ∈ C. Set w = z1 , so that z = 1 w. Substituting this back into the equation for A gives α 1 1 1 1 + β + β + γ = 0. ww w w Multiplying through by ww, we see that w satisfies the equation α + βw + βw + γww = 0. As α and γ are real and as the coefficients of w and w are complex conjugates, this is again the equation of a circle in C. 2. QED 2. 2 about the circle in C J(A) in terms of the circle in C A. As a specific example, let A be the circle in C given by the equation 2z+2z+3 = 0.

The same argument gives that m ◦ f (H(− 12 )) = H(− 12 ), and hence that both H(− 12 ) ∩ V (0) = − 12 i and H(− 12 ) ∩ V (1) = 1 − 12 i lie in Z. Each pair of points in Z gives rise to a Euclidean line that is taken to itself by m ◦ f , and each triple of noncolinear points in Z gives rise to a Euclidean circle that is taken to itself by m ◦ f . The intersections of these Euclidean lines and Euclidean circles give rise to more points of Z, which in turn give rise to more Euclidean lines and Euclidean circles taken to themselves, and so on.

Consider the function τ : M¨ ob+ → C defined by setting τ (m) = (a + d)2 , where m(z) = az+b cz+d is normalized. As the only ambiguity in the definition of a normalized M¨ obius transformation arises from multiplying all coefficients by −1, we see that τ (m) is well defined. In fact, this possible ambiguity is why we consider the function τ and not the actual trace trace(m) = a + d. As with the trace of a matrix, one useful property of τ is that it is invariant under conjugation. 23 Show that τ (m ◦ n) = τ (n ◦ m).

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